If a 5 kg object is being constantly accelerated from 0m/s to 12 m/s over 6s, how much power is being applied at t= 1 ?

1 Answer
Jan 25, 2016

Here,power= 20W

Explanation:

First,
v=12m/s
u=0m/s
t=6s

Therefore,a=(v-u)/t

a=12/6=2m/s

Since acceleration is constant=2m/s
now v at t=2s

#v=u+at=0+1x2=2#
                therefore #v=2#

p=FXV
P=10X2=20W