If a #5 kg# object is being constantly accelerated from #0m/s# to #12 m/s# over # 6s#, how much power is being applied at #t= 1 #?

1 Answer
Wricheek
Jan 25, 2016

Here,#power#= 20#W#

Explanation:

First,
#v#=12m/s
#u#=0m/s
#t#=6s

Therefore,#a=(v-u)/t#

#a=12/6=2m/s#

Since acceleration is constant=#2m/s#
now #v # at #t=2s#

#v=u+at=0+1x2=2#
                therefore #v=2#

#p=FXV#
#P=10X2=20W#

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