How do you rewrite $y + 5 = 3 (x - 9)$ $y + 5 = 3(x-9)$ in standard form?

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Answer 1 · 2016-01-23T14:37:02

$y - 3 x + 32 = 0$ $y - 3x+32=0$

$y + 5 = 3 (x - 9)$ $y + 5 = 3(x-9)$

first, multiple the 3 with the bracket

$y + 5 = 3 (x) - 3 (9)$ $y + 5 = 3(x)-3(9)$

then, this what you will get

$y + 5 = 3 x - 27$ $y + 5 = 3x-27$

move the right side to left side,

$y + 5 - 3 x + 27 = 0$ $y + 5 - 3x+27=0$

solve the 5 and 27, and finally u will get the answer

$y - 3 x + 32 = 0$ $y - 3x+32=0$

How do you rewrite y+5=3(x−9)y + 5 = 3(x-9) in standard form?