How do you solve #9(2x-1)+x=3(6x-3)#?

1 Answer
Kris Caceres
Jan 19, 2016

PEMDAS. x=0

Explanation:

To solve this, you have to simplify the equation using PEMDAS; Parenthesis, Exponent, Multiplication, Division, Addition and Subtraction.

First, simplify what's inside the parenthesis. But this does not apply to given equation. There's also no exponent involved so let's just move to multiplication,

#9(2x-1) + x = 3(6x - 3)#
#(18x - 9) +x = (18x - 9)# or #(18x - 9 +x = 18x - 9#

combine common terms,
#19x - 9 = 18x - 9#

Then, isolate x by transposing it and combine common terms to solve it,
#19x - 18x = -9 +9#
#x = 0#

checking the solution:
#x = 0#

#9(2x-1) + x = 3(6x - 3)#
#9(2(0)-1) + (0) = 3(6(0) - 3)#
#9(-1) = 3(-3)#
#-9 = -9#

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