What is the mass in #3.01 * 10^23# molecules of #F_2#?

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Answer 1 · 2016-01-16T15:21:34

The answer to this is #1.14 * 10^25 grams #

To convert mol #F_2# to grams #F_2#, you simply have to multiply the given number of mol to the molar mass of the compound.

For this case:

#g F_2 = (3.01 * 10^(23) mol) * (37.996 g/[mol] )#

#g F_2 = 1.1436796 * 10^(23)#

Using correct number of significant figures,
#g F_2 = 1.14 * 10^25 grams #

note:
molar mass of #F_2# means you have to multiply Fluorine's molar mass by 2.

molar mass of #F_2 = 2 * ( 18.992 g/[mol]) = 37.996 g/[mol] #