What is the zeros of the function $h(x) = (4-9x^2)/(2x-5)$ ?

Question

1114 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-01-11T14:19:11

$x = +- 2/3$

A fraction is zero if and only if its numerator is zero.

Thus, $h(x) = 0 iff -9x^2 + 4 = 0 iff 9x^2 = 4 iff x^2 = 4/9 iff x = +- 2/3$ .

We can keep both solutions because none of them is a zero of the denominator.

What is the zeros of the function h(x) = (4-9x^2)/(2x-5)h(x) = (4-9x^2)/(2x-5)?