How do you solve the rational equation $\frac{y + 2}{y} = \frac{1}{y - 5}$ $(y+2)/y = 1/(y-5)$ ?

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How do you solve the rational equation $\frac{y + 2}{y} = \frac{1}{y - 5}$ $(y+2)/y = 1/(y-5)$ ?

1 Answer

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Answer 1 · 2016-01-10T11:37:12

$y = 2 \pm \sqrt{14}$ $y=2+-sqrt(14)$

Explanation:

Multiply through by the denominators to remove the fractions.

$(y + 2) (y - 5) = y$ $(y+2)(y-5)=y$

Expand and solve.

$y^{2} - 3 y - 10 = y$ $y^2-3y-10=y$
$y^{2} - 4 y - 10 = 0$ $y^2-4y-10=0$
${(y - 2)}^{2} - 14 = 0$ $(y-2)^2-14=0$
$y = 2 \pm \sqrt{14}$ $y=2+-sqrt(14)$

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How do you solve the rational equation $\frac{y + 2}{y} = \frac{1}{y - 5}$ $(y+2)/y = 1/(y-5)$ ?

1 Answer

Explanation:

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How do you solve the rational equation (y+2)/y = 1/(y-5)y+2y=1y−5(y+2)/y = 1/(y-5)?

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Explanation:

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How do you solve the rational equation $\frac{y + 2}{y} = \frac{1}{y - 5}$ $(y+2)/y = 1/(y-5)$ ?