How can i find a plane #P# with #A(0,-1,1) in P#, #B(-1,2,3) in P# and parallel to the y axis ?

1 Answer
Topscooter
Jan 6, 2016

It doesn't exist.

Explanation:

Your plane needs to have one constant parameter. Here, #x# should be constant. Think about #RR^2# : a line parallel to the #y# axis has the form #x = a# so in #RR^3# a plane parallel to the #y# axis has the form #{x = a, y in RR, z in RR}#.

So such a plan doesn't exist.

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