How can i find a plane $P$ $P$ with $A (0, - 1, 1) \in P$ $A(0,-1,1) in P$ , $B (- 1, 2, 3) \in P$ $B(-1,2,3) in P$ and parallel to the y axis ?

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How can i find a plane $P$ $P$ with $A (0, - 1, 1) \in P$ $A(0,-1,1) in P$ , $B (- 1, 2, 3) \in P$ $B(-1,2,3) in P$ and parallel to the y axis ?

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Answer 1 · 2016-01-06T21:55:32

It doesn't exist.

Explanation:

Your plane needs to have one constant parameter. Here, $x$ $x$ should be constant. Think about $RR^2$ : a line parallel to the $y$ axis has the form $x = a$ so in $RR^3$ a plane parallel to the $y$ axis has the form ${x = a, y in RR, z in RR}$ .

So such a plan doesn't exist.

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How can i find a plane $P$ $P$ with $A (0, - 1, 1) \in P$ $A(0,-1,1) in P$ , $B (- 1, 2, 3) \in P$ $B(-1,2,3) in P$ and parallel to the y axis ?

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Explanation:

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How can i find a plane PPP with A(0,-1,1) in PA(0,−1,1)∈PA(0,-1,1) in P, B(-1,2,3) in PB(−1,2,3)∈PB(-1,2,3) in P and parallel to the y axis ?

1 Answer

Explanation:

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How can i find a plane $P$ $P$ with $A (0, - 1, 1) \in P$ $A(0,-1,1) in P$ , $B (- 1, 2, 3) \in P$ $B(-1,2,3) in P$ and parallel to the y axis ?