In order to open the clam it catches, a seagull will drop the clam repeatedly onto a hard surface from high in the air until the shell cracks. If a seagull flies to a height of 27 m, how long will the clam take to fall?

Question

In order to open the clam it catches, a seagull will drop the clam repeatedly onto a hard surface from high in the air until the shell cracks. If a seagull flies to a height of 27 m, how long will the clam take to fall?

2 Answers

Impact of this question

12243 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-01-06T17:09:19

I found: $2.3 s$ $2.3s$

Explanation:

The shell will fall with zero initial velocity (dropped) and under the action of acceleration of gravity $g$ $g$ .
We can use:
$y_{f} - y_{i} = v_{i} t + \frac{1}{2} \cdot a t^{2}$ $color(red)(y_f-y_i=v_it+1/2*at^2)$

$0 - 27 = 0 t - \frac{1}{2} \cdot 9.8 t^{2}$ $0-27=0t-1/2*9.8t^2$
$t = \sqrt{\frac{2 \cdot 27}{9.8}} = 2.3 s$ $t=sqrt((2*27)/9.8)=2.3s$

Answer 2 · 2016-01-06T17:13:57

$2.3 s$ $2.3s$ (2sf), Assuming dropped from rest vertically with no air resistance.

Explanation:

Assuming that we are treating the clam as falling vertically from rest with no air resistance, the following should sort it:

Downwards is positive.

$s = 27 m$ $s=27m$
$u = 0 m s^{- 1}$ $u=0ms^-1$
$v = v m s^{- 1}$ $v=vms^-1$
$a = g = 9.81 m s^{- 2}$ $a=g=9.81ms^-2$
$t = ? s$ $t=?s$

We are looking for $t$ $t$ , and with the information we have, we don't need to worry about $v$ $v$ .

Use the constant acceleration equation:
$s = u t + \frac{1}{2} a t^{2}$ $s=ut+1/2at^2$

$27 = \frac{1}{2} (g) t^{2}$ $27=1/2(g)t^2$

$t^{2} = \frac{54}{9.81}$ $t^2=54/9.81$

$t=2.34618....s$

$t=2.3s$ (2sf)

Science

Math

Humanities

... and beyond

In order to open the clam it catches, a seagull will drop the clam repeatedly onto a hard surface from high in the air until the shell cracks. If a seagull flies to a height of 27 m, how long will the clam take to fall?

2 Answers

Explanation:

Explanation:

Related questions

Impact of this question