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What is the electron configuration of Au+?

1 Answer

Jan 3, 2016

#[Xe] 4f^14 5d^10#

Explanation:

The atomic number of Au is 79.

Therefore, its configuration is:

#1s^2 2s^2 2p^6 3s^2 3p^6 3d^10 4s^2 4p^6 4d^10 5s^2 5p^6 4f^14 5d^10 6s^1#

or, #[Xe] 4f^14 5d^10 6s^1#

For #Au^+#, one electron is removed from the outermost #6s# orbital, making the configuration,

#[Xe] 4f^14 5d^10#

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