If a current of $4 A$ $4 A$ passing through a circuit generates $48 W$ $48 W$ of power, what is the resistance of the circuit?

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If a current of $4 A$ $4 A$ passing through a circuit generates $48 W$ $48 W$ of power, what is the resistance of the circuit?

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Answer 1 · 2016-01-03T12:22:02

$3Omega$

Explanation:

$P=I^2R$

Where $P$ is power, $I$ is current, and $R$ is resistance.

Rearrange for $R$ :

$R=P/I^2$

Substitute in values:

$R=48/4^2$

$R=48/16$

$R=3Omega$

Answer 2 · 2016-01-03T12:28:43

$Omega = 3 " ohm"$

Explanation:

$Power = "Voltage" * "Current"$
$"Resistance" = "Voltage"/"Current"$ , so
$"Voltage"= "Resistance" * "Current"$ , and
$Power = ("Resistance" * "Current") * "Current"$
$Power = "Resistance" * "Current"^2$

In numbers:
$48"W" = Omega * 4^2"A"$
$48/16 = Omega$
$Omega = 3 " ohm"$

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If a current of $4 A$ $4 A$ passing through a circuit generates $48 W$ $48 W$ of power, what is the resistance of the circuit?

2 Answers

Explanation:

Explanation:

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If a current of 4 A4A4 A passing through a circuit generates 48 W48W48 W of power, what is the resistance of the circuit?

2 Answers

Explanation:

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If a current of $4 A$ $4 A$ passing through a circuit generates $48 W$ $48 W$ of power, what is the resistance of the circuit?