How do you find the equation of the circle, given the center and radius (0,0);4?

1 Answer
Jan 3, 2016

The equation of the circle would be x^2+y^2=16x2+y2=16

Explanation:

The general equation of a circle is:
(x-a)^2+(y-b)^2=r^2(xa)2+(yb)2=r2
where aa is the xx coordinate of the center, bb is the yy coordinate of the center, and rr is the radius of the circle.

Applying this to your conditions, we get:
(x-0)^2+(y-0)^2=4^2(x0)2+(y0)2=42

which is

x^2+y^2=16x2+y2=16