How do you find the equation of the circle, given the center and radius (0,0);4?

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How do you find the equation of the circle, given the center and radius (0,0);4?

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Answer 1 · 2016-01-03T12:12:09

The equation of the circle would be $x^{2} + y^{2} = 16$ $x^2+y^2=16$

Explanation:

The general equation of a circle is:
${(x - a)}^{2} + {(y - b)}^{2} = r^{2}$ $(x-a)^2+(y-b)^2=r^2$
where $a$ $a$ is the $x$ $x$ coordinate of the center, $b$ $b$ is the $y$ $y$ coordinate of the center, and $r$ $r$ is the radius of the circle.

Applying this to your conditions, we get:
${(x - 0)}^{2} + {(y - 0)}^{2} = 4^{2}$ $(x-0)^2+(y-0)^2=4^2$

which is

$x^{2} + y^{2} = 16$ $x^2+y^2=16$

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How do you find the equation of the circle, given the center and radius (0,0);4?

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