A projectile is shot at an angle of $\frac{π}{6}$ $pi/6$ and a velocity of $8 \frac{m}{s}$ $8 m/s$ . How far away will the projectile land?

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A projectile is shot at an angle of $\frac{π}{6}$ $pi/6$ and a velocity of $8 \frac{m}{s}$ $8 m/s$ . How far away will the projectile land?

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Answer 1 · 2016-01-02T21:58:00

The projectile will land $5.68 m$ $5.68m$ far.

Explanation:

Find the time when the projectile lands with the vertical equation $v t - \frac{1}{2} a t^{2} = 0$ $vt-1/2at^2=0$ so $t (v - \frac{1}{2} a t) = 0$ $t(v-1/2at)=0$ $t(fall)=2v/g=(2vsin30°)/g=0.82s$
We use this value in the horizontal equation $s(x)=v*t(fall)$
So $s=vcos30°*t(fall)=5.68m$

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A projectile is shot at an angle of $\frac{π}{6}$ $pi/6$ and a velocity of $8 \frac{m}{s}$ $8 m/s$ . How far away will the projectile land?

1 Answer

Explanation:

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A projectile is shot at an angle of $\frac{π}{6}$ $pi/6$ and a velocity of $8 \frac{m}{s}$ $8 m/s$ . How far away will the projectile land?