A speed boat moving at a velocity of 25 m/s runs out of gas and drifts to a stop 3 minutes later 100 meters away. What is its rate of deceleration?

1 Answer
Dec 30, 2015

0.139 m/s^2

Explanation:

From Newton's Equations of Motion, we have:

v=u+at

where,
v is the final velocity of the boat,
u is the initial velocity of the boat,
a is the acceleration of the boat,
t is the time taken by the boat to accelerate/decelerate from u to v.

Since the boat decelerates from 25 m/s to a stop (which is 0 m/s) in 3 minutes (=3*60=180 seconds, since all units must be from the SI system),

u=25 m/s

v=0 m/s

t=180 s

Substituting these values in the above equation, we have:

0=25+a*180

-25=a*180

a=-25/180=-0.139 m/s^2

The negative sign indicates that the boat has decelerated. We can simply write that deceleration is equal to 0.139 m/s^2