What is the kinetic energy of an object with a mass of $3 k g$ $3 kg$ that has been in freefall for $4 s$ $4 s$ ?

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What is the kinetic energy of an object with a mass of $3 k g$ $3 kg$ that has been in freefall for $4 s$ $4 s$ ?

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Answer 1 · 2015-12-30T13:00:41

The kinetic energy of the object is $K = 2310 N$ $K=2310N$

Explanation:

You know that the formula of kinetic energy is $K = \frac{1}{2} m v^{2}$ $K=1/2mv^2$
At $t = 0$ $t=0$ $v = 0$ $v=0$ , so after $4 s$ $4s$ the speed of the object will be $v = a t = 9.81 \frac{m}{s^{2}} \cdot 4 s = 39.24 \frac{m}{s}$ $v=at=9.81m/s^2*4s=39.24m/s$
So $K = 2310 N$ $K=2310N$

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What is the kinetic energy of an object with a mass of $3 k g$ $3 kg$ that has been in freefall for $4 s$ $4 s$ ?

1 Answer

Explanation:

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What is the kinetic energy of an object with a mass of 3kg3 kg that has been in freefall for 4s4 s?

1 Answer

Explanation:

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What is the kinetic energy of an object with a mass of $3 k g$ $3 kg$ that has been in freefall for $4 s$ $4 s$ ?