A projectile is shot at an angle of $\frac{π}{6}$ $pi/6$ and a velocity of $24 \frac{m}{s}$ $24 m/s$ . How far away will the projectile land?

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A projectile is shot at an angle of $\frac{π}{6}$ $pi/6$ and a velocity of $24 \frac{m}{s}$ $24 m/s$ . How far away will the projectile land?

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Answer 1 · 2015-12-30T12:54:30

The projectile will land $50.9 m$ $50.9m$ far.

Explanation:

Find the time t when the projectile lands, with the vertical equation $s (y) = v t - \frac{1}{2} a t^{2} = 0$ $s(y)=vt-1/2at^2=0$ ; $t = 2 \frac{v}{g}$ $t=2v/g$ with $v=vsin30°$
So $t(fall)=2.45m$
Use this value in the horizontal equation to find the lenght of the motion:
$s(x)=vt$ with $v=vcos30°$ and $t=t(fall)$
$s(t)=(vcos30°)*(t(fall))=50.9m$

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A projectile is shot at an angle of $\frac{π}{6}$ $pi/6$ and a velocity of $24 \frac{m}{s}$ $24 m/s$ . How far away will the projectile land?

1 Answer

Explanation:

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A projectile is shot at an angle of $\frac{π}{6}$ $pi/6$ and a velocity of $24 \frac{m}{s}$ $24 m/s$ . How far away will the projectile land?