A projectile is shot at an angle of $\frac{π}{6}$ $pi/6$ and a velocity of $2 \frac{m}{s}$ $2 m/s$ . How far away will the projectile land?

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A projectile is shot at an angle of $\frac{π}{6}$ $pi/6$ and a velocity of $2 \frac{m}{s}$ $2 m/s$ . How far away will the projectile land?

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Answer 1 · 2015-12-29T20:21:17

The projectile will fall $0.35 m$ $0.35m$ far.

Explanation:

Find the moment when the projectile fall and use the vertical equation $s (y) = v t - \frac{1}{2} a t^{2} = 0$ $s(y)=vt-1/2at^2=0$ ; $t (f a l l) = 2 \frac{v}{g} = \frac{2 \cdot v sin 30}{g} = 0.2 s$ $t(fall)=2v/g=(2*vsin30)/g=0.2s$ and subsitute this value in the horizontal equation
$s(t)=vt=(vcos30°)*0.2=0.35m$

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A projectile is shot at an angle of $\frac{π}{6}$ $pi/6$ and a velocity of $2 \frac{m}{s}$ $2 m/s$ . How far away will the projectile land?

1 Answer

Explanation:

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A projectile is shot at an angle of $\frac{π}{6}$ $pi/6$ and a velocity of $2 \frac{m}{s}$ $2 m/s$ . How far away will the projectile land?