If a projectile is shot at an angle of $\frac{π}{4}$ $pi/4$ and at a velocity of $15 \frac{m}{s}$ $15 m/s$ , when will it reach its maximum height??

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If a projectile is shot at an angle of $\frac{π}{4}$ $pi/4$ and at a velocity of $15 \frac{m}{s}$ $15 m/s$ , when will it reach its maximum height??

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Answer 1 · 2015-12-28T11:09:06

The projectile will reach its maximum height at 1.08 s

Explanation:

This is the classical parabolas motion problem.
Let's consider the equation of speed $v = v - a t$ $v=v-at$ for the vertical component.
When the projectile will reach its maximum the vertical component will be 0.
So $v - a t = 0$ $v-at=0$ and $t = \frac{v}{g}$ $t=v/g$ . Obviously we consider the vertical component of speed $v=vsin45°$ and use this value in the last formula. We find $t=(vsin45°)/g=1.08s$ .
That's all.

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If a projectile is shot at an angle of $\frac{π}{4}$ $pi/4$ and at a velocity of $15 \frac{m}{s}$ $15 m/s$ , when will it reach its maximum height??

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If a projectile is shot at an angle of $\frac{π}{4}$ $pi/4$ and at a velocity of $15 \frac{m}{s}$ $15 m/s$ , when will it reach its maximum height??