If a projectile is shot at an angle of (2pi)/3 and at a velocity of 6 m/s, when will it reach its maximum height?

1 Answer
Dec 27, 2015

The projectile will reach its maximum height at 0.53 s

Explanation:

We consider the equation
s=vt-1/2at^2 and v=v-at
we find the moment when the horizontal component of speed is 0 (the vertical component is v(x)=vsin(a))
so we have the equation v-at=0
a is equal to g, so t=v/g=0.53 m/s^2