What would be the formula between Aluminum $A l^{+ 3}$ $Al^(+3)$ and Sulfate $S O_{4}^{- 2}$ $SO_4 ^(-2)$ ?

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What would be the formula between Aluminum $A l^{+ 3}$ $Al^(+3)$ and Sulfate $S O_{4}^{- 2}$ $SO_4 ^(-2)$ ?

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Answer 1 · 2015-12-24T16:10:25

$A l_{2} {(S O_{4})}_{3}$ $Al_2(SO_4)_3$

Explanation:

$A l^{+ 3} + S O_{4}^{- 2}$ $Al^(+3)+SO_4^-2$ → $A l_{2} {(S O_{4})}_{3}$ $Al_2(SO_4)_3$

To get this you would have to balance the charges between the anion and metal cation.

Do this by finding the least common multiple between the parts. In this case it turns out to be 6. Therefore we need 2 moles of $A l^{+ 3}$ $Al^(+3)$ and 3 moles of $S O_{4}^{- 2}$ $SO_4^-2$ to balance the charges.

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What would be the formula between Aluminum $A l^{+ 3}$ $Al^(+3)$ and Sulfate $S O_{4}^{- 2}$ $SO_4 ^(-2)$ ?

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Explanation:

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What would be the formula between Aluminum Al^(+3)Al+3Al^(+3) and Sulfate SO_4 ^(-2)SO−24SO_4 ^(-2)?

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What would be the formula between Aluminum $A l^{+ 3}$ $Al^(+3)$ and Sulfate $S O_{4}^{- 2}$ $SO_4 ^(-2)$ ?