How do you factor the trinomial $6 y^{2} + 72 y + 192 = 0$ $6y ^2 + 72y + 192 = 0$ ?

Question

1871 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-12-19T22:40:52

$6 (y + 8) (y + 4)$ $6(y+8)(y+4)$

The trinomial can be simplified by factoring out $6$ $6$

You then have the following:

$6 (y^{2} + 12 y + 32) = 0$ $6(y^2+12y+32)=0$

This should make things easier to factor

Now find two numbers that when added together equal $12$ $12$ and when multiplied equal $32$ $32$

How do you factor the trinomial 6y2+72y+192=06y ^2 + 72y + 192 = 0?