How do you differentiate $g (x) = (2 + 4 e^{x}) (2 x + 2 x^{2})$ $g(x) = (2 + 4e^x) ( 2x + 2x^2)$ using the product rule?

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How do you differentiate $g (x) = (2 + 4 e^{x}) (2 x + 2 x^{2})$ $g(x) = (2 + 4e^x) ( 2x + 2x^2)$ using the product rule?

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Answer 1 · 2015-12-19T17:08:01

$g'(x) = 4e^x(2x+2x^2) + (4x+2)(2+4e^x)$

Explanation:

$g$ is the product of two functions $u(x) = 2+4e^x$ and $v(x) = 2x+2x^2$
By the product rule, $g' = u'v + uv'$ . Here, $u'(x) = 4e^x$ and $v'(x) = 4x+2$ .

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How do you differentiate $g (x) = (2 + 4 e^{x}) (2 x + 2 x^{2})$ $g(x) = (2 + 4e^x) ( 2x + 2x^2)$ using the product rule?

1 Answer

Explanation:

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How do you differentiate g(x) = (2 + 4e^x) ( 2x + 2x^2)g(x)=(2+4ex)(2x+2x2)g(x) = (2 + 4e^x) ( 2x + 2x^2) using the product rule?

1 Answer

Explanation:

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How do you differentiate $g (x) = (2 + 4 e^{x}) (2 x + 2 x^{2})$ $g(x) = (2 + 4e^x) ( 2x + 2x^2)$ using the product rule?