How do you factor 8x^3*y^6 + 27? Algebra Polynomials and Factoring Factor Polynomials Using Special Products 1 Answer mason m Dec 13, 2015 (2xy^2+3)(4x^2y^4-6xy^2+9) Explanation: Sum of cubes: (a^3+b^3)=(a+b)(a^2-ab+b^2) Since 8x^3y^6+27=(2xy^2)^3+(3)^3, a=2xy^2 b=3 8x^3y^6+27=(2xy^2+3)(4x^2y^4-6xy^2+9) Answer link Related questions How do you factor special products of polynomials? How do you identify special products when factoring? How do you factor x^3 -8? What are the factors of x^3y^6 – 64? How do you know if x^2 + 10x + 25 is a perfect square? How do you write 16x^2 – 48x + 36 as a perfect square trinomial? What is the difference of two squares method of factoring? How do you factor 16x^2-36 using the difference of squares? How do you factor 2x^4y^2-32? How do you factor x^2 - 27? See all questions in Factor Polynomials Using Special Products Impact of this question 1841 views around the world You can reuse this answer Creative Commons License