What is #1##1/2# #+# #2# #1/4# #+# #6^2#?

1 Answer
Dec 11, 2015

#159/4# is the answer

Explanation:

Before you can actually add of the numbers together, you must get all the denominators to be equal.

Most of the time, it is easiest to change all the denominators to the highest number denominator.

For this, that would be the 4. So our goal is to make all the fractions become out of 4.
For the first part, #1 1/2# we must make it into a improper fraction first. To do this, we multiply the 1 out front times the 2 to get #2/2# then we add the other 1 from the numerator to get #3/2#.
Then to make it out of 4, we multiply the numerator and denominator times 2 separately and then we get #6/4#.
Then with the #6^2# we square the #6# to get #36#.

Then to get it over 4, we multiply the #36*4# to get #144# and put it over 4 like so: #144/4#
Now that we have all the denominators the same, we can add.
#6/4 + 9/4 + 144/4#

#6+9+144=159#
And the denominator stays the same, #4# so #159/4# is the answer.