Question #ad06e

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Answer 1 · 2015-12-07T15:28:43

#t = x^(1/3)#

#dt = 1/3x^(-2/3)#

#3int1/3(e^root(3) (x))^3 /x^(2/3) dx #

become

#3int(e^t)^3dt = 3inte^(3t)dt#

#u = 3t#
#du = 3#

#inte^udu = [e^u]+C#

Substitute back...