What is the equation of the line passing through $(-1,-1)$ and $(1,14)$ ?

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Answer 1 · 2015-12-07T12:30:50

$15x-2y=-13$

Slope= $(y2-y1)/(x2-x1)$
Slope= $(14+1)/(1+1)$
Slope= $15/2$

Equation of line passing through 2 points is $y-y1=m(x-x1)$
where $m$ is the slope

So the equation of the line is $y+1=15/2(x+1)$
$2y+2=15x+15$
$15x-2y=-13$

What is the equation of the line passing through (-1,-1)(-1,-1) and (1,14)(1,14)?