While you cook on your gas grill, 3.7 grams of #CO_2# are produced. How many moles of propane, #C_3H_8# are used, using the equation #C_3H_8+5O_2 -> 3CO_2+4H_2O#?

1 Answer
MAT
Dec 2, 2015

0.084 moles of #C_3H_8#

Explanation:

Given mass of #CO_2# = 3.7g
Molar mass of #CO_2# = 12+2(16)= 44g/mol
No of moles of #CO_2# produced = #("given mass")/("molar mass")# = #3.7/44# =0.084mol

According to balanced equation;
3 moles of #CO_2# requires = 1 mole of #C_3H_8#
Thus, 0.084 moles of #CO_2# will require= #1/3 xx 0.084#mol of #C_3H_8#
= 0.028mol of #C_3H_8#
So, 0.028mol of #C_3H_8# are used to produce 3.7g of #CO_2#

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