How do you factor $9x(3x-9)^2 + (3x-9)^3$ ?

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Answer 1 · 2015-11-22T16:25:57

$=3(4x-3)(3x-9)^2$

$9x(3x-9)^2+(3x-9)^3 = (9x + 3x -9)(3x-9)^2$

$=(12x - 9)(3x-9)^2$

$=3(4x-3)(3x-9)^2$

You know that

$(3x-9)^2= [3(x-3)]^2 = 9 * (x-3)^2$

The expression becomes

$3(4x-3)(3x-9)^2 = 27 * (4x-3)(x-3)^2$

How do you factor 9x(3x-9)^2 + (3x-9)^39x(3x-9)^2 + (3x-9)^3?