How do you factor #9x(3x-9)^2 + (3x-9)^3#?
1 Answer
Nov 22, 2015
Explanation:
#9x(3x-9)^2+(3x-9)^3 = (9x + 3x -9)(3x-9)^2#
#=(12x - 9)(3x-9)^2#
#=3(4x-3)(3x-9)^2#
You know that
#(3x-9)^2= [3(x-3)]^2 = 9 * (x-3)^2#
The expression becomes
#3(4x-3)(3x-9)^2 = 27 * (4x-3)(x-3)^2#
