How do you implicitly differentiate $y {sin x}^{2} = x e^{- y} sin (e^{y})$ $ysinx^2 = xe^-ysin(e^y)$ ?

Question

How do you implicitly differentiate $y {sin x}^{2} = x e^{- y} sin (e^{y})$ $ysinx^2 = xe^-ysin(e^y)$ ?

1 Answer

Impact of this question

1814 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-11-21T21:28:43

$\frac{d y}{d x} . {sin x}^{2} + 2 x y {cos x}^{2} = e^{- y} {sin e}^{y} + x (- e^{- y} . \frac{d y}{d x} . {sin e}^{y} + \frac{d y}{d x} {cos e}^{y})$ $dy/dx.sinx^2 + 2xycosx^2 = e^-y sine^y + x( -e^-y. dy/dx.sine^y + dy/dx cos e^y)$

Science

Math

Humanities

... and beyond

How do you implicitly differentiate $y {sin x}^{2} = x e^{- y} sin (e^{y})$ $ysinx^2 = xe^-ysin(e^y)$ ?

1 Answer

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you implicitly differentiate ysinx^2 = xe^-ysin(e^y)ysinx2=xe−ysin(ey) ysinx^2 = xe^-ysin(e^y)?

1 Answer

Related questions

Impact of this question

How do you implicitly differentiate $y {sin x}^{2} = x e^{- y} sin (e^{y})$ $ysinx^2 = xe^-ysin(e^y)$ ?