How do you implicitly differentiate $sin (x y) + x^{2} = x - y$ $sin(xy)+x^2=x-y$ ?

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Answer 1 · 2015-11-21T21:03:42

The derivative is $(y + x \frac{d y}{d x}) . cos (x y) + 2 x = 1 - \frac{d y}{d x}$ $(y + x dy/dx).cos(xy) + 2x = 1 - dy/dx$

How do you implicitly differentiate sin(xy)+x^2=x-y sin(xy)+x2=x−y sin(xy)+x^2=x-y ?