Question #92817

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Question #92817

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Answer 1 · 2015-11-20T10:41:10

$30 N$ $30N$

Explanation:

The tension in the strings provide the necessary centripetal force.
Now, centripetal force $F_{c} = \frac{m \cdot v^{2}}{r}$ $F_c=(m*v^2)/r$
Here, $m = 20 k g$ $m=20kg$ , $v = 3 m s^{- 1}$ $v=3ms^-1$ , $r = 3 m$ $r=3m$
So $F_{c} = 60 N$ $F_c=60N$
But this force is divided between two ropes.
So the force on each rope is $\frac{F_{c}}{2}$ $F_c/2$ i.e $30 N$ $30N$
This force is the maximum tension.

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Question #92817

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