What is the discriminant of # 0 = x^2 + 4x + 4#?

1 Answer
Kashan Hanif
Nov 19, 2015

Discriminant#(Delta)=0#

Explanation:

Given a second degree equation in the general form:
#ax^2+bx+c=0#
the discriminant is:
#Delta=b^2-4ac#

Here,
#a=1, b=4 and c=4#
So,
#Delta=color(red)4^2-4color(red)((1)(4))#
#Delta=16-16#
#Delta=0#

which means the given equation has two coincident real solutions.

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