What is the standard form of $y = (- 6 x - 5) (2 x - 3)$ $y= (-6x-5)(2x-3)$ ?

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Answer 1 · 2015-11-18T17:51:00

The answer to your question is:
$y = - 12 x^{2} + 8 x + 15$ $y=-12x^2+8x+15$

First you need to get rid of the parenthesis. After that you have to look wether or not you can simplify it:

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What is the standard form of y= (-6x-5)(2x-3) y=(−6x−5)(2x−3)y= (-6x-5)(2x-3) ?