How do you factor $2 a^{4} + 21 a^{3} + 49 a^{2}$ $2a^4+21a^3+49a^2$ ?

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How do you factor $2 a^{4} + 21 a^{3} + 49 a^{2}$ $2a^4+21a^3+49a^2$ ?

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Answer 1 · 2015-11-17T18:13:25

$a^{2} (a + 7) (2 a + 7)$ $a^2(a+7)(2a+7)$

Explanation:

$2 a^{4} + 21 a^{3} + 49 a^{2}$ $2a^4+21a^3+49a^2$
= $a^{2} (2 a^{2} + 21 a + 49)$ $a^2(2a^2+21a+49)$
= $a^{2} (2 a^{2} + 14 a + 7 a + 49)$ $a^2(2a^2+14a+7a+49)$
= $a^{2} [2 a (a + 7) + 7 (a + 7)]$ $a^2[2a(a+7)+7(a+7)]$
= $a^{2} (a + 7) (2 a + 7)$ $a^2(a+7)(2a+7)$

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How do you factor $2 a^{4} + 21 a^{3} + 49 a^{2}$ $2a^4+21a^3+49a^2$ ?

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How do you factor $2 a^{4} + 21 a^{3} + 49 a^{2}$ $2a^4+21a^3+49a^2$ ?