What is the equation of the line passing through (93,78)(93,78) and (-68,44)(68,44)?

1 Answer
Nov 14, 2015

Find the line in the form y = mx + by=mx+b.
The slope can be found through the formula m=(y_2-y_1)/(x_2-x_1)m=y2y1x2x1.
Thus, color(red)(m)=(44-78)/(-68-93)=(-34)/-161=color(red)(34/161)m=44786893=34161=34161

Now, find bb by plugging mm into y = mx + by=mx+b with one of the points.

With the point (93,78)(93,78): 78 = (34/161)93+b78=(34161)93+b
Multiply: 78 = 3162/161+b78=3162161+b
Find a common denominator: 12558/161=3162/161+b12558161=3162161+b
Subtract 3162/1613162161 from both sides: color(red)(9396/161=b)9396161=b
This cannot be simplified.

Plug back into y=mx+by=mx+b: color(red)(y=34/(161)x+9396/161)y=34161x+9396161

This can also be written as y=(34x+9396)/161y=34x+9396161