How do you factor #15x^2 - 65x - 50 #?

1 Answer
Hugo C.
Nov 13, 2015

#(3x+2)(x-5)#.
#x = -2/3#,
#x = 5#.

Explanation:

We start with:
#15x^2 - 65x - 50#.

First of all, we can simplify by dividing #5#.
#5(3x^2 - 13x - 10)#. This can be written as:
#3x^2 - 13x - 10#.

We now multiply the factor of #x^2#, (3) by the last number (-10).
We get #-30#. We now have to look for multiples that add to -13 and multiply to #-30#. These are #2# and #-15#.

We now lay out the equation as:
#((3x + 2)(3x -15))/3#. We can divide the sec on bracket by 3, leaving us with:
#(3x+2)(x-5)#, which is the final answer.

Hope it Helps! :D .

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