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How do you solve x = 4y + 8 and 2x - 8y = -3?

1 Answer

Nov 5, 2015

This system has no solutions.

Explanation:

This system has no solutions. Multiplying by #2# the first equation, we have

#2x=8y+16#, which we can rewrite as #2x-8y=16#. So, the system becomes

#{ (2x-8y=+16),(2x-8y=-3):}#

And you can see this is impossible: if the same quantity (namely #2x-8y#) is equal to both #16# and #-3#, then also #16=-3#, which is clearly false.

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