What is the surface area to volume ratio for a cube that measures 8 cm on each side?

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What is the surface area to volume ratio for a cube that measures 8 cm on each side?

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Answer 1 · 2015-11-04T07:10:58

$0, 75 {cm}^{- 1}$ $0,75 "cm"^-1$

Explanation:

First, you have to calculate the surface of your cube.

Surface of one face : $s = 8 \cdot 8 = 64 {cm}^{2}$ $"s" = 8*8=64 "cm"^2$
Total surface (surface of one side multiplied by the number of
sides) : $S = 64 \cdot 6 = 384 {cm}^{2}$ $"S" =64*6=384 "cm"^2$

Second, calculate the volume

$V = s \cdot hauteur = 64 \cdot 8 = 512 {cm}^{3}$ $"V" = "s"*"hauteur" = 64*8 = 512 "cm"^3$

Finally, the surface to volume ratio R :

$R = \frac{S}{V} = \frac{384}{512} = 0, 75 {cm}^{- 1}$ $"R" ="S"/"V"= 384/512 = 0,75 "cm"^-1$

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What is the surface area to volume ratio for a cube that measures 8 cm on each side?

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