Question #181c1

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Answer 1 · 2015-11-02T07:50:10

F = 28000N

Given, force of engine = 40000 N

Force of friction = 5000 N

Mass of engine = 8000 kg

Total weight of wagons = 5 x 2000 kg = 10000 kg

The net accelerating force

= Force exerted by engine – Force of fricition

= 40000 N – 5000 N = 35000 N

The acceleration of the train

We know that, F = mass x acceleration

Or, 35000 N = (mass of engine + mass of 5 wagons) X a

Or, 35000 N = (8000 kg + 10000 kg) X a

Or, 35000N = 18000 kg X a
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The force of wagon 1 on wagon 2

Since, net accelerating force = 35000 N

Mass of all 5 wagons = 10000 kg

We know that, F = m x a

Therefore, 35000N = 10000 kg x a
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