How do you simplify $4^{- 2}$ $4^-2$ ?

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How do you simplify $4^{- 2}$ $4^-2$ ?

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Answer 1 · 2015-10-28T00:54:32

$\frac{1}{16}$ $1/16$

Explanation:

Anything with a negative exponent is the inverse of it. So for example if I had $2^{- 2}$ $2^-2$ , I would write it as $\frac{1}{2^{2}}$ $1/2^2$ .

Now for your question:
$4^{- 2} = \frac{1}{4^{2}} = \frac{1}{16} = 0.0625$ $4^-2 = 1/4^2 = 1/16=0.0625$

Answer 2 · 2015-10-28T00:56:32

The answer is $\frac{1}{16}$ $1/16$ .

Explanation:

The negative sign in the -2 exponent implies that the number changes sides in a fraction. In other words, the $4^{- 2}$ $4^-2$ would move to the denominator. It would simplify to $\frac{1}{4^{2}}$ $1/4^2$ , or $\frac{1}{16}$ $1/16$ .

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How do you simplify $4^{- 2}$ $4^-2$ ?

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