What does ((1+i)*(6-2i))/(4i) equal?

1 Answer
Oct 21, 2015

1-2i

Explanation:

Given equation = ((1+i)(6-2i))/4i

Expand the numerator

= (6-2i+6i-2i^2)/(4i)
= (6+4i-2(-1))/(4i)
= (6+4i+2)/(4i)
= (8+4i)/(4i)
Take 4 as common in numerator
= (4(2+i))/(4i)
=(2+i)/(i)
multiply numerator and denominator with i
= (2i+i^2)/(i^2)
= (2i-1)/(-1)
= 1-2i