How do you solve $(sqrt(3))^(2x+4)=9^(x-2)$ ?

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Answer 1 · 2015-10-09T16:30:04

X = 6

$(sqrt3)^(2X+4)$ = $9^(X-2)$

$3^(1/2(2X+4)$ = $3^(2(X-2)$
$3^((X+2)$ = $3^(2X-4)$

Take ln both sides

$ln(3^((X+2)))$ = $ln(3^(2X-4))$

X+2 (ln3) = 2X-4 ( ln3)

ln3 on both side cancels,
X+2 = 2X-4
Rearrange terms

2+4 = 2X-X

6 =- X

How do you solve (sqrt(3))^(2x+4)=9^(x-2) (sqrt(3))^(2x+4)=9^(x-2)?