Question #4a60a

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Answer 1 · 2015-10-09T06:38:45

I have modified question since question posed is not conveying what you want really and answer for modified question is given below

HCl reacts with hydroxide ( $KOH, Be(OH)_2 and Ga(OH)_3$ ) to form respective salts and water for neutralization reaction.

$HCl + KOH rarr KCl + H_2O$

Therefore 0.1 mole of KOH is required to neutralise HCl

$2HCl + Be(OH)_2 rarr BeCl_2 + 2H_2O$

For this reaction 0.05 mole of $Be(OH)_2$ is required for neutralization of HCl

$3HCl + Ga(OH)_3 rarr GaCl_3 + 3H_2O$

For this reaction 0.033 mole of $Ga(OH)_3$ is required for neutralization of HCl

But other compounds do not react hence therefore HCl can not act as the limiting reagent but merely depends on their solubility