How do you solve #-x^2-4x>3#?

Question

How do you solve #-x^2-4x>3#?

1 Answer

Impact of this question

1851 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-09-27T17:15:53

#-3 < x <-1#

Explanation:

#-x^2-4x>3=># multiply by -1, reverse direction of inequality:
#x^2+4x<-3=># solving by completing the square:
#x^2+4x+4<4-3#
#(x+2)^2<1#
#-1 < (x+2)<1#
#-3 < x <-1#
In interval form:
#(-3, -1)#

Science

Math

Humanities

... and beyond

How do you solve #-x^2-4x>3#?

1 Answer

Explanation:

Related questions

Impact of this question