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How do you simplify #sqrt 80 / sqrt 5#?

2 Answers

Konstantinos Michailidis

Sep 17, 2015

It is #sqrt80/sqrt5=(sqrt((5*16)/5))=sqrt(16)=4#

Sep 17, 2015

#4#

Explanation:

#sqrt80/sqrt5# can also be written as #sqrt((80/5)# or #(80/5)^(1/2)#

Simplify #80/5# or in other terms, divide #80# by #5#;

#=sqrt((cancel(80)16)/(cancel(5)1))#

#=sqrt16#

#=4#

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