How do you simplify #sqrtxsqrt(x+2)#?

1 Answer
Aron S.
Sep 16, 2015

#sqrt(x)sqrt(x+2) = sqrt(x(x+2))#

Explanation:

#sqrt(a)sqrt(b) = sqrt(ab)# when #a# and #b# are non-negative, which means you can join them under the same square root to #sqrt(x)sqrt(x+2) = sqrt(x(x+2))#, which is the simplest form.

Apart from expanding it to #sqrt(x^2+2x)#, there's not much more to do with this expression.

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