How do you write #f(x)=4x^2-12x+5# in factored form? Algebra Polynomials and Factoring Factoring Completely 1 Answer Nabil A. Sep 14, 2015 #f(x) = (2x - 5) (2x - 1)# Explanation: #f(x) = 4x^2 - 12x + 5# #f(x) = ((4x - 10) (4x - 2)) /4# #4 * 5 = 20# You want factors of 20 that add to 12. #f(x) = (cancel(2)(2x - 5) cancel(2)(2x - 1))/cancel(4)# #f(x) = (2x - 5) (2x - 1)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 5147 views around the world You can reuse this answer Creative Commons License