How do you write $\frac{x^{2}}{y^{- 3}}$ $x^2 / y^-3$ with a postive exponent?

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Answer 1 · 2015-09-07T15:04:57

$x^{2} y^{3}$ $x^2y^3$

Recall that $a^{- n} = \frac{1}{a^{n}}$ $a^-n = 1/a^n$ .

$\frac{x^{2}}{y^{- 3}}$ $x^2/y^-3$

$= \frac{x^{2}}{\frac{1}{y^{3}}}$ $=x^2/(1/y^3)$

$= x^{2} y^{3}$ $=x^2y^3$

How do you write x2y−3x^2 / y^-3 with a postive exponent?