How do you solve #.05(1.15)^x = 5#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer dani83 Sep 2, 2015 # x = log_1.15 100 # Explanation: # log a^n = n log a # # log_a b = log_c b/log_c a # # 0.05(1.15)^x = 5 # # 1.15^x = 100 # # xlog 1.15 = log 100 # # x = log_1.15 100 # Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 3449 views around the world You can reuse this answer Creative Commons License