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How do you solve #20 (100 - e^(x/2)) = 500#?

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1 Answer

Aug 6, 2015

#x=log(5625)=3.75# 2 d.p.

Explanation:

Rearrange the expression as follows:

#20(100-e^(x/2))=500# => #e^(x/2)=75#

Take logarithms =f both sides:

#loge^(x/2)=x/2=log(75)# => #x=2log(75)=log(75^2)=log(5625)#

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