If x varies inversely as y, and x = 13 when y = 9, how do you find x when y = 0, 3, 6, 12, 15, 18?

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Answer 1 · 2015-07-09T20:26:21

#x = 117/y#

x varies inversely as y #\Leftrightarrow x \propto 1/y, y \ne 0#
#x = f(y) = k * 1/y#

#13 = f(9) = k/9#

#13 * 9 = k#

#x(3) = (13 * 9) / 3 = 39#

#x(6) = (13 * 9) / 6 = 39 / 2#

#x(12) = (13 * 9) / 12 = 39/4#

#x(15) = (13 * 9) / 15 = 39/5#

#x(18) = (13 * 9) / 18 = 13 / 2#